Thursday, December 10, 2009

Math question?

k the question is:



Conor walked from his house to the movies and jogged home. he walked at 5km/h and jogged at 7km/h. If Conor was walking for two hours more than he jogged, how far is his house from the movie theater?



k could you guys show all youre work, i need to learn how to do it so just set up the equation and show youre work. i think you need to set up two different equations.



thanks everyone



Math question?concert tickets



This can be solved using Linear Equations in one variable...



Let the time used by Connoer be represented by x hrs.



Since Distance = Speed x Time... And the distance from the house to the movies and vice-versa is same....



We get the equation,



5 ( x + 2 ) = 7x



5x + 10 = 7x



7x - 2x = 10



5x = 10



x = 2 hrs...



Therefore to cover the distance by running, he took 2 hours...



Therefore, since Distance = Speed x Time



Therefore, Distance = 7 kms/hr x 2 hrs



= 14 kms.



Therefore, the distance from the movies to the home is 14 kms..



Hope this helps...



Math question?theater seating opera theater



let the distance be X



than the equation is X = 5 *( X/7 ) + 10



7X = 5X/7 + 10



7X = 5X + 70



7X - 5X = 70



2X = 70



X = 35, ur ans is here, Distance is 35 KM
Simultaneous equation:



x = time it took to walk



y = time it took to jog



x = y + 2 (the time it took to walk is equal to the time it took to jog, plus 2 hours)



5x = 7y (the time it took to walk times the speed is equal in distance to the time it took to jog times the speed.)



Substitution:



Since x = y + 2, and we are trying to get an equation with only 1 variable, then you can substitute y + 2 for x in the other equation.



So:



5(y + 2) = 7y



5y + 10 = 7y (simplify the left side of the equation)



10 = 2y (subtract 5y from each side)



5 = y (divide each side by 2)



Find out the x variable:



x = y + 2



x = 5 + 2 (substitute the value of y for y)



x = 7 (simplify)



Check:



5(7) = 7(5)



35 = 35



Answer the problem in words, since it is a word problem:



It took Conor 7 hours to walk to the movie theatre and 5 hours to jog back. (that is not the answer)



This is the answer:



It is 35 miles to the movie store. (since distance = speed * time, and 5 (speed of walking) * 7 (amount of time) = 35, and 7 * 5 = 35)
home --%26gt; movie at 5 km/hr



movie --%26gt; home at 7 km/hr



let x be the number of hours it takes for conor to job back



5 km/hr * (x + 2)hr = 7 km/hr * x hr



5x + 10 = 7x



10 = 2x



x = 5 hrs to jog



7 km/hr * 5 hrs = 35 km distance from house to movie



therefore conor lives 35 km from the movies
Tw=Time walking Tj=Time jogging



D=D



5Tw=7Tj



Tw-2=Tj



start with that^



Then since you know that Tj = Tw-2 you can substitute that for Tj down



5Tw=7(Tw-2)



Then you distribute the 7



5Tw=7Tw-14



subtract the 7 Tw from the 5Tw which gives you the below equation



-2Tw=-14



and then you divide both sides by negative 2 and get the below



Tw=7



Then you multiply that by the rate she was walking at to get the distance



7(5)=35

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